document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330733>Question 330733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has a perimeter of 84 inches. its shortest side measures 9 inches shorter than its middle side,and its longest side measures 6inches longer than its middle side. find the lengths of the triangle three sides </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237115 by </B><A HREF=/tutors/aboutme.mpl?userid=dewasmaharaja><B>dewasmaharaja(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dewasmaharaja><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let three sides of the triangle be<BR>\n" );
document.write( "l for long<BR>\n" );
document.write( "m for middle<BR>\n" );
document.write( "s for short\r<BR>\n" );
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document.write( "Then,<BR>\n" );
document.write( "l + m + s = 84 ...(a)<BR>\n" );
document.write( "s = m - 9 ...(b)<BR>\n" );
document.write( "l = m + 6 ...(c)\r<BR>\n" );
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document.write( "Substituting equation (b) and (c) in (a),\r<BR>\n" );
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document.write( "m - 9 + m + m + 6 = 84\r<BR>\n" );
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document.write( "3m = 87<BR>\n" );
document.write( "Therefore, m = 87/3 = 29\r<BR>\n" );
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document.write( "From (b), s = 29 - 9 = 20<BR>\n" );
document.write( "From (c), l = 29 + 6 = 35 </SPAN>\n" );
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