document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330751>Question 330751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motor boat takes 4 hours to travel 352 km going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237109 by </B><A HREF=/tutors/aboutme.mpl?userid=dewasmaharaja><B>dewasmaharaja(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dewasmaharaja><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let speed of boat in still water be x km/hr. and speed of stream be y km/hr.\r<BR>\n" );
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document.write( "Therefore,\r<BR>\n" );
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document.write( "Upstream, effective speed of boat = x - y = 352/4 = 88. This means, x = y + 88\r<BR>\n" );
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document.write( "Downstream, effective speed of boat = x + y = 352/2 = 176\r<BR>\n" );
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document.write( "Substituting value of x, \r<BR>\n" );
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document.write( "y + 88 + y = 176<BR>\n" );
document.write( "2y = 176 - 88 = 88<BR>\n" );
document.write( "Speed of stream, y = 44 km/hr<BR>\n" );
document.write( "Speed of boat in still water, x = 44 + 88 = 132 km/hr </SPAN>\n" );
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