document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38218>Question 38218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve for A:  2A/3=8+4A?  Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23706 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "2A/3 = 8 + 4A<BR>\n" );
document.write( "let us multiply both sides by 3 to clear the fractions<BR>\n" );
document.write( "2A = 24 + 12A<BR>\n" );
document.write( "now subtract 12A from both sides<BR>\n" );
document.write( "-10A = 24<BR>\n" );
document.write( "now divide both sides by -10 and reduce<BR>\n" );
document.write( "A = 24/-10 = -12/5 </SPAN>\n" );
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