document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330052>Question 330052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Plane X leaves airport 1 and heads for airport 2 which is a distance of 2,700 km. At the same time, plane Y leaves airport 2 and heads for airport 1. Due to headwinds and tailwinds, Plane X's average speed is 100 kph greater than that of plane Y. If the two planes pass each other after 3 hours, find the speed of each plane. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #237058 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=237058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> they close the distance of 2700 km in 3 hr , so the sum of their speeds is 2700/3 or 900 kph\r<BR>\n" );
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document.write( "X + Y = 900 ___ and ___ X = Y + 100\r<BR>\n" );
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document.write( "substitute to solve the system </SPAN>\n" );
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