document.write( "Question 328768: Cars arrive at a toll both according to a Poisson process with mean 80 cars per hour. If the attendant makes a one-minute phone call, what is the probability that at least 1 car arrives during the call? \n" ); document.write( "

Algebra.Com's Answer #237057 by jrfrunner(365) $\"\"$ $\"About$

You can put this solution on YOUR website!
X=number of car passing in an interval of time\r
\n" ); document.write( "\n" ); document.write( "X~Poisson (mean=80/hour) or Poisson (mean 80/60min=4/3min)\r
\n" ); document.write( "\n" ); document.write( " $\"P%28X=x%29=+mean%5E%28x%29%2Ae%5E%28-mean%29%2Fx%21+\"$ where x>=0)
\n" ); document.write( " $\"P%28X=x%29=+%284%2F3%29%5Ex+%2Ae%5E%28-4%2F3%29%2Fx%21\"$ \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P(at least one car)= 1- P(no cars passing in the interval of interest)
\n" ); document.write( "P(X>=1)= 1-P(X=0) = $\"1+-+e%5E%28-4%2F3%29\"$ = 1-0.264=0.736 \n" ); document.write( "

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