document.write( "Question 330635: A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9^2, where h is the height, in meters, from which the launch occurs, at velocity v meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 110 meters high with an initial upward speed of 30 meters per second, what will its height be after 3 seconds.\r
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document.write( "Please help..... \n" );
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Algebra.Com's Answer #237031 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The first thing I need to do is to correct your height function. The gravitational acceleration term is based on the square of time, not the square of the gravitation coefficient. Furthermore, I like to work with my polynomials in standard form, hence:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "All you need to do is plug in the given numbers and do the indicated arithmetic:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll leave you alone so you can spend some quality time with your calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |