document.write( "Question 330579: Hypatia could row 90 miles downstream in 6 hours but required 8 hours to row 72 miles upstream. What was her speed in still water and what was the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #237025 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "90=R*6
\n" ); document.write( "R=90/6
\n" ); document.write( "R=15 MPH.
\n" ); document.write( "72=R*8
\n" ); document.write( "R=72/8
\n" ); document.write( "R=9 MPH.
\n" ); document.write( "(15+9)/2=24/2=12 MPH. IS THE RATE OF BOAT IN STILL WATER.
\n" ); document.write( "(15-9)/2=6/2=3 MPH. IS THE RATE OF THE STREAM.
\n" ); document.write( "PROOF:
\n" ); document.write( "90=(12+3)*6
\n" ); document.write( "90=15*6
\n" ); document.write( "90=90
\n" ); document.write( "72=(12-3)*8
\n" ); document.write( "72=9*8
\n" ); document.write( "72=72
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