document.write( "Question 329835: I have no idea where to start with this.... Thanks for your help!\r
\n" ); document.write( "\n" ); document.write( "11 out of 40 students are selected for a team each year. 15/40 participated once in the last two years. What is the probability of selecting 3 but no more than 5 students from the 15 that previously participated.
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Algebra.Com's Answer #236963 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
you want to select n=11 students out of N=40
\n" ); document.write( "15 have participated once in the last 2 years, 25 have not\r
\n" ); document.write( "\n" ); document.write( "X=# in the 11 which participated previously\r
\n" ); document.write( "\n" ); document.write( "You need P(X=3,4 or 5) = P(X=3)+P(X=4)+P(X=5)\r
\n" ); document.write( "\n" ); document.write( "There are 40C11 ways to select the 11 students out of 40 =2,311,801,440
\n" ); document.write( "There are 15C3*25C8 ways to select 3 students from the 15 who prev participated and 25C8 ways to select 8 students from the 25 that did not = 544*1,081,575 = 492,116,625\r
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\n" ); document.write( "\n" ); document.write( "P(X=3,4,5) = (15C3*25C8 + 15C4*25C7 + 15C5*25C6)/40C11 =1,680,103,425/2,311,801,440=0.727\r
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