document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330540>Question 330540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 20.  The length is 3 less than twice the width.  Find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236945 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width of the rectangle be w<BR>\n" );
document.write( "The length is 3 less than twice the width<BR>\n" );
document.write( "so the length = 2w-3\r<BR>\n" );
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document.write( "given area = 20\r<BR>\n" );
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document.write( "so w(2w-3)=20\r<BR>\n" );
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document.write( "so 2w^2-3w-20=0\r<BR>\n" );
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document.write( "=> 2w^2-8w+5w-20=0<BR>\n" );
document.write( "=> 2w(w-4)+5(w-4)=0\r<BR>\n" );
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document.write( "so (2w+5)(w-4)=0\r<BR>\n" );
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document.write( "so w=4 or w=-5/2\r<BR>\n" );
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document.write( "since width can't be negative \r<BR>\n" );
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document.write( "the width of the rectangle is = 4\r<BR>\n" );
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document.write( "so the length will be = 5 \r<BR>\n" );
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document.write( "Ans: length=5 width=4 </SPAN>\n" );
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