document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330520>Question 330520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jar of dimes and quarters contained $10.95. There were only 93 coins in the jar. How many dimes were in the jar? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236942 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the no. of dimes be x<BR>\n" );
document.write( "and no. of quarters be y\r<BR>\n" );
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document.write( "There were only 93 coins in the jar\r<BR>\n" );
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document.write( "so x+y=93 ----- eq. 1 \r<BR>\n" );
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document.write( "also one dime = 10 cents<BR>\n" );
document.write( "and one quarter = 25 cents\r<BR>\n" );
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document.write( "so 10x+25y=1095\r<BR>\n" );
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document.write( "   10x+10y=930 (from equation 1)\r<BR>\n" );
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document.write( " => 15y=165 (subtracting one eq. from another)\r<BR>\n" );
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document.write( " => y=11\r<BR>\n" );
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document.write( "and x=82\r<BR>\n" );
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document.write( "so no. of dimes in the jar=82 </SPAN>\n" );
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