document.write( "Question 330514: If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? Use the hang-time function V=48t^2\r
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document.write( "His hang time is in how many seconds? \n" );
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Algebra.Com's Answer #236919 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? Use the hang-time function V=48t^2\r \n" ); document.write( "\n" ); document.write( "His hang time is in how many seconds? \n" ); document.write( ". \n" ); document.write( "V is given as 35 inches -- plug this into the equation and solve for t: \n" ); document.write( "V=48t^2 \n" ); document.write( "35=48t^2 \n" ); document.write( "35/48 = t^2 \n" ); document.write( "sqrt(35/48) = t \n" ); document.write( "0.85 secs = t \n" ); document.write( " |