document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38212>Question 38212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble finding the volume and surface area of a cone. The lateral side is 10 ft and the base is 9ft.. This is a right cone,don't know if it makes a difference. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23690 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a right circular cone, the volume is<BR>\n" );
document.write( "V = (1/3)(pi)(r^2)h and the surface area (in terms of the lateral side s) is<BR>\n" );
document.write( "A = (pi)r^2 + (pi)rs<BR>\n" );
document.write( "You haven't specified whether the 9 ft is the radius or diameter, but given these formulas and the one relating height to radius and lateral side, s^2 = r^2 + h^2, you can plug everything in and go... </SPAN>\n" );
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