document.write( "Question 330494: please find the equation of the tangent to the curve given by
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document.write( "y= x^3 - 5x + 15
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document.write( "at the point where x= -1
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document.write( "I got the answer to be
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document.write( "y= -2x +17
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document.write( "but im not sure if this is right.
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document.write( "could you show working if im incorrect please.thanks \n" );
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Algebra.Com's Answer #236895 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! The slope of the tangent line equals the value of the derivative at x=-1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "At \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use the point-slope form of a line, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "That's what I get too. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " |