document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330488>Question 330488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 square centimeters, find the width of the rectangle to the nearest thousandth. \r<BR>\n" );
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document.write( "Thank you for the service you offer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236885 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width = x<BR>\n" );
document.write( "length = 2x+3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ARea = L*W<BR>\n" );
document.write( "x(2x+3)=93<BR>\n" );
document.write( "2x^2+3x=93<BR>\n" );
document.write( "2x^2+3x-93=0\r<BR>\n" );
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document.write( "quadratic formula<BR>\n" );
document.write( "x1=(-b+sqrt(b^2-4ac))/2a<BR>\n" );
document.write( "a=2, b=3, c=-93<BR>\n" );
document.write( "x1=(-3+sqrt(9+744))/4<BR>\n" );
document.write( "x1= 6.110 cm the width<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x2=(-3-sqrt(9+744))/4<BR>\n" );
document.write( "x2= -7.610  Ignore the negative value </SPAN>\n" );
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