document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330393>Question 330393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem. The book says to find all real and imaginary solutions by method of choice. Thank you\r<BR>\n" );
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document.write( "   2x-5 = &#8730;7x+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236843 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-5=sqrt(7x+7) Assuming that this is the problem.<BR>\n" );
document.write( "4x^2-20x+25=7x+7 Square each side.<BR>\n" );
document.write( "4x^2-27x+18=0<BR>\n" );
document.write( "4*18=72. the 2 factors of 72 whose sum is -27 are -24 and -3.<BR>\n" );
document.write( "4x^2-3x-24x+18=0<BR>\n" );
document.write( "x(4x-3)-6(4x-3)=0<BR>\n" );
document.write( "(x-6)(4x-3)=0<BR>\n" );
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document.write( "x=6<BR>\n" );
document.write( "4x=3, x=3/4<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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