document.write( "Question 330421: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
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document.write( "the length is ___ in
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document.write( "the width is ____ in \n" );
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Algebra.Com's Answer #236841 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's have x represent width and x+50 be the length. Now we can set up and equation as: \n" ); document.write( "2x+2(x+50)=200 \n" ); document.write( "Combine like terms to get: \n" ); document.write( "4x+100=200 \n" ); document.write( "Now subtract 100 and divide by 4 to get: \n" ); document.write( "x=25 \n" ); document.write( "So now we know the width is 25 inches and the length is 75 inches. \r \n" ); document.write( "\n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( " |