document.write( "Question 330421: the perimeter of a rectangle is 200 inches The length exceeds the width by 50 inches. find the length and the width.
\n" ); document.write( "the length is ___ in
\n" ); document.write( "the width is ____ in
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Algebra.Com's Answer #236841 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let's have x represent width and x+50 be the length. Now we can set up and equation as:
\n" ); document.write( "2x+2(x+50)=200
\n" ); document.write( "Combine like terms to get:
\n" ); document.write( "4x+100=200
\n" ); document.write( "Now subtract 100 and divide by 4 to get:
\n" ); document.write( "x=25
\n" ); document.write( "So now we know the width is 25 inches and the length is 75 inches. \r
\n" ); document.write( "\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
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