document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330436>Question 330436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
document.write( "\n" );
document.write( "Need to find the exact and approximate solutions to three decimal places for the following:  (x-6)^2=20.\r<BR>\n" );
document.write( "\n" );
document.write( "I am unable to solve, and have even tried using Algebrator, but cannot interpret.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236836 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking square root ___ x - 6 = ± sqrt(20) = ± 2 sqrt(5)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "adding 6 ___ x = 6 ± 2 sqrt(5)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "use calculator to find 2 sqrt(5) , add to and subtract from 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );