document.write( "Question 330388: I need to solve |4x-1|≤4\r
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document.write( "This is absolute value and inequality but I cannot figure it out. Thanks in advance for your help. \n" );
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Algebra.Com's Answer #236829 by scott8148(6628) You can put this solution on YOUR website! the absolute value of the quantity must be less than or equal to 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means the quantity must be greater than (or equal to) -4 ... (-3 , -2 , -1 ,etc.) \n" ); document.write( "___ AND less than (or equal to) 4 ... (3 , 2 , 1 , etc)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4 ≤ (4x - 1) ≤4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "adding 1 ___ -3 ≤ 4x ≤ 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "dividing by 4 ___ (-3/4) ≤ x ≤ (5/4) \n" ); document.write( " |