document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330404>Question 330404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a canoe can travel 12 miles upstream in the same amount of time it takes to travel 30 miles downstream. if the speed of the current is 6 miles per hour, what was the speed of the canoe in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236798 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of canoe in still water be x<BR>\n" );
document.write( "speed of current = 6mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "speed with current = x+6 mph<BR>\n" );
document.write( "speed against current = x-6 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time = distance /rate<BR>\n" );
document.write( "12/x-6 = 30/x+6  (upstream / down stream  times are same )<BR>\n" );
document.write( "12(x+6)=30(x-6)<BR>\n" );
document.write( "12x+72=30x-180<BR>\n" );
document.write( "-18x=-252<BR>\n" );
document.write( "x=14 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );