document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330287>Question 330287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack usually mows his lawn in 4 hours. Marilyn can mow the same lawn in 7 hours. How much time would it take for them to mow the lawn together? It would take tham how many hours of they worked together?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236795 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> they each mow a FRACTION of the lawn , based on their individual times ___ the fractions sum to one , the whole lawn\r<BR>\n" );
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document.write( "let t=\"time together\"\r<BR>\n" );
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document.write( "(t / 4) + (t / 7) = 1\r<BR>\n" );
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document.write( "multiplying by 28 (the LCD) ___ 7t + 4t = 28 ___ 11t = 28 </SPAN>\n" );
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