document.write( "Question 330333: Solve.\r
\n" ); document.write( "\n" ); document.write( "x= 2 sqrt(x+3)\r
\n" ); document.write( "\n" ); document.write( "Please help \n" ); document.write( "

Algebra.Com's Answer #236793 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Square both sides.
\n" ); document.write( " $\"x%5E2=4%28x%2B3%29\"$
\n" ); document.write( " $\"x%5E2-4x-12=0\"$
\n" ); document.write( " $\"x%5E2-4x%2B4-16=0\"$
\n" ); document.write( " $\"%28x-2%29%5E2=16\"$
\n" ); document.write( " $\"x-2=0+%2B-+4\"$
\n" ); document.write( " $\"x=2%2B-4\"$
\n" ); document.write( " $\"x1=6\"$ and $\"x2=-2\"$
\n" ); document.write( " \n" ); document.write( "

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