document.write( "Question 330347: when a ball is thrown, it's height in feet H after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second if v=13 feet per second find all the values of t for which h=2 \n" ); document.write( "
Algebra.Com's Answer #236770 by Alan3354(69443)\"\" \"About 
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when a ball is thrown, it's [sic] height in feet H after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second if v=13 feet per second find all the values of t for which h=2
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\n" ); document.write( "h(t) = vt-16t^2
\n" ); document.write( "Sub 2 for h and 13 for h
\n" ); document.write( "2 = 13t - 16t^2
\n" ); document.write( "16t^2 - 13t + 2 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-16x%5E2%2B13x%2B-2+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2813%29%5E2-4%2A-16%2A-2=41\".
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\n" ); document.write( " Discriminant d=41 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-13%2B-sqrt%28+41+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2813%29%2Bsqrt%28+41+%29%29%2F2%5C-16+=+0.206152367580223\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2813%29-sqrt%28+41+%29%29%2F2%5C-16+=+0.606347632419777\"
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\n" ); document.write( " Quadratic expression \"-16x%5E2%2B13x%2B-2\" can be factored:
\n" ); document.write( " \"-16x%5E2%2B13x%2B-2+=+%28x-0.206152367580223%29%2A%28x-0.606347632419777%29\"
\n" ); document.write( " Again, the answer is: 0.206152367580223, 0.606347632419777.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B13%2Ax%2B-2+%29\"

\n" ); document.write( "\n" ); document.write( "t = x
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\n" ); document.write( "It's at 2 feet twice, going up, then coming back down.
\n" ); document.write( "Most people find it difficult to throw a ball straight up from ground level.\r
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