document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=326907>Question 326907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then :\r<BR>\n" );
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document.write( "a- p(a and b)= 0.70<BR>\n" );
document.write( "b- p(a or b)= 0.64<BR>\n" );
document.write( "c- p(a and b)= 0.64<BR>\n" );
document.write( "d- p(a or b)= 0.70\r<BR>\n" );
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document.write( "thanks\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236763 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if A and B are independent then P(A and B) = P(A)*P(B) = 0.1*0.6=0.06<BR>\n" );
document.write( "also P(A or B) = P(A)+P(B)-P(A and B)= P(A)+P(B)-P(A)*P(B)<BR>\n" );
document.write( "               = 0.1 +0.6-0.1*0.6=0.7-0.06=0.64 </SPAN>\n" );
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