document.write( "Question 38177This question is from textbook Heath Algebra 2 An Integrated Approach
\n" ); document.write( ": Please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "\"6e%5E%28-x%29=3\"
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Algebra.Com's Answer #23676 by fractalier(6550)\"\" \"About 
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Okay, from 6e^(-x) = 3
\n" ); document.write( "we'll divide by 6 first and get
\n" ); document.write( "e^(-x) = 1/2
\n" ); document.write( "then take the ln of both sides
\n" ); document.write( "ln[e^(-x)] = ln(1/2)
\n" ); document.write( "-x = ln(1/2)
\n" ); document.write( "x = -ln(1/2)
\n" ); document.write( "x = ln 2
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