document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330281>Question 330281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this.<BR>\n" );
document.write( "6^(2-m)=2^(3m+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236721 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6^(2-m)=2^(3m+1)<BR>\n" );
document.write( "(2-m)*log(6) = (3m+1)*log(2)<BR>\n" );
document.write( "Can you finish it?<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "log(6) and log(2) are just numbers.<BR>\n" );
document.write( "2log(6) - mlog(6) = 3mlog(2) + log(2)<BR>\n" );
document.write( "3mlog(2) + mlog(6) = 2log(6) - log(2) = log(36) - log(2) = log(18)<BR>\n" );
document.write( "m*(3log(2) + log(6)) = log(18)<BR>\n" );
document.write( "m*(log(8) + log(6)) = log(18)<BR>\n" );
document.write( "m*log(48) = log(18)<BR>\n" );
document.write( "m = log(18)/log(48)<BR>\n" );
document.write( "m =~ 0.74663438<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );