document.write( "Question 330195: Find three consecutive multiples of 5 such that the sum of the squares of the first two is 125 greater than the square of the third.\r
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document.write( "This is what I did, but it's wrong.\r
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document.write( "25N + 25N + 25 - 125 = 25N + 100
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document.write( "25N - 100 = 100
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document.write( "25N = 200
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document.write( "N = 8 \n" );
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Algebra.Com's Answer #236635 by hanah(4)![]() ![]() ![]() You can put this solution on YOUR website! N=2 \n" ); document.write( " |