document.write( "Question 330195: Find three consecutive multiples of 5 such that the sum of the squares of the first two is 125 greater than the square of the third.\r
\n" ); document.write( "\n" ); document.write( "This is what I did, but it's wrong.\r
\n" ); document.write( "\n" ); document.write( "\"%285N%29%5E2+%2B+%285N%2B5%29%5E2+-+125+=+%285N%2B10%29%5E2\"
\n" ); document.write( "25N + 25N + 25 - 125 = 25N + 100
\n" ); document.write( "25N - 100 = 100
\n" ); document.write( "25N = 200
\n" ); document.write( "N = 8
\n" ); document.write( "

Algebra.Com's Answer #236635 by hanah(4)\"\" \"About 
You can put this solution on YOUR website!
N=2 \n" ); document.write( "
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