document.write( "Question 330095: I have been having problems solving this problem. It says to solve with all extraneous solutions. Thank you for your time to help\r
\n" ); document.write( "\n" ); document.write( "5÷y-3 = y+7÷2y-6 +1
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Algebra.Com's Answer #236619 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"5%2F%28y-3%29+=+%28y%2B7%29%2F%282y-6%29++%2B1\"
\n" ); document.write( "\"5%2F%28y-3%29+=+%28%281%2F2%29%2A%28y%2B7%29%29%2F%28y-3%29++%2B%28y-3%29%2F%28y-3%29\"
\n" ); document.write( "\"5%2F%28y-3%29+=+%28%281%2F2%29%2A%28y%2B7%29%2B%28y-3%29%29%2F%28y-3%29\"
\n" ); document.write( "Multiply both sides by \"y-3\".
\n" ); document.write( "\"5+=+%281%2F2%29%2A%28y%2B7%29%2B%28y-3%29\"
\n" ); document.write( "\"10+=+%28y%2B7%29%2B2%28y-3%29\"
\n" ); document.write( "\"y%2B7%2B2y-6=10\"
\n" ); document.write( "\"3y%2B1=10\"
\n" ); document.write( "\"3y=9\"
\n" ); document.write( "\"y=3\"
\n" ); document.write( "This solution is not allowed since the assumption was made that y did not equal 3 when multiplying both sides by \"y-3\".
\n" ); document.write( "No solution.\r
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