document.write( "Question 38199: A home was purchased for $120,000 in 2001. After one year the home had appreciated 5%. After one more year, the home had appreciated an additional 4%. What was the value of the home after these two years, rounded to the nearest hundred dollars?
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document.write( "A) $124,800 B) $126,000 C) $130,800 D) $131,000\r
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document.write( ". A new car is marked down from $28,000 to $25,200. What is the discount rate?
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document.write( "A) 9% B) 11% C) 10% D) 15% \n" );
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Algebra.Com's Answer #23658 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! P = purchase price \n" ); document.write( "a = rate of appreciation \n" ); document.write( "V(1) = value after 1 year \n" ); document.write( "V(2) = value after 2 years \n" ); document.write( "The first year, a = 5% \n" ); document.write( "P = 120000 \n" ); document.write( "V(1) = P + aP \n" ); document.write( "V(1) = 120000 + (.05)(120000) \n" ); document.write( "V(1) = 120000(1 + .05) \n" ); document.write( "V(1) = 126000 \n" ); document.write( "V(2) = V(1) + aV(1) \n" ); document.write( "V(2) = 126000 + (.04)(126000) \n" ); document.write( "V(2) = 126000(1 + .04) \n" ); document.write( "V(2) = 131040 \n" ); document.write( "the answere is (d) 131,000 \n" ); document.write( "discount rate = (original price) - (discounted price) / (original price) \n" ); document.write( "28000 - 25200 = 2800 \n" ); document.write( "2800 / 28000 = .10 \n" ); document.write( "the answer is (c) 10% \n" ); document.write( " |