document.write( "Question 38199: A home was purchased for $120,000 in 2001. After one year the home had appreciated 5%. After one more year, the home had appreciated an additional 4%. What was the value of the home after these two years, rounded to the nearest hundred dollars?
\n" ); document.write( "A) $124,800 B) $126,000 C) $130,800 D) $131,000\r
\n" ); document.write( "\n" ); document.write( ". A new car is marked down from $28,000 to $25,200. What is the discount rate?
\n" ); document.write( "A) 9% B) 11% C) 10% D) 15%
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Algebra.Com's Answer #23658 by josmiceli(19441)\"\" \"About 
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P = purchase price
\n" ); document.write( "a = rate of appreciation
\n" ); document.write( "V(1) = value after 1 year
\n" ); document.write( "V(2) = value after 2 years
\n" ); document.write( "The first year, a = 5%
\n" ); document.write( "P = 120000
\n" ); document.write( "V(1) = P + aP
\n" ); document.write( "V(1) = 120000 + (.05)(120000)
\n" ); document.write( "V(1) = 120000(1 + .05)
\n" ); document.write( "V(1) = 126000
\n" ); document.write( "V(2) = V(1) + aV(1)
\n" ); document.write( "V(2) = 126000 + (.04)(126000)
\n" ); document.write( "V(2) = 126000(1 + .04)
\n" ); document.write( "V(2) = 131040
\n" ); document.write( "the answere is (d) 131,000
\n" ); document.write( "discount rate = (original price) - (discounted price) / (original price)
\n" ); document.write( "28000 - 25200 = 2800
\n" ); document.write( "2800 / 28000 = .10
\n" ); document.write( "the answer is (c) 10%
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