document.write( "Question 38158: ok I need to graph and get the intercepts for the problem y = -4x^2 +16x - 12 I know its a downward cone shape but I cannot get the vertex or the intercepts right. \n" ); document.write( "
Algebra.Com's Answer #23656 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
Hey ... we did this one on the phone today. :) Glad you made it to the site :)\r
\n" ); document.write( "\n" ); document.write( "\"+y+=+-4x%5E2+%2B16x+-+12+\"
\n" ); document.write( "For the intercepts, assume y = 0
\n" ); document.write( "\"+0+=+-4x%5E2+%2B16x+-+12+\"
\n" ); document.write( "Divide by -4 throughout
\n" ); document.write( "\"+0+=+x%5E2+%2B+4x+-+3+\"
\n" ); document.write( "factor
\n" ); document.write( "\"+0+=+%28x-3%29%28x-1%29+\"
\n" ); document.write( "set both parts equal to 0
\n" ); document.write( "\"+0+-+x-3+\" and \"+0+=+x+-+1+\"
\n" ); document.write( "x = {1, 3}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now for the line os symmetry ... \"+x+=+-b%2F2a+\"
\n" ); document.write( "use the +16 from the Original equation
\n" ); document.write( "\"+x+=+-16%2F2%28-4%29+\"
\n" ); document.write( "\"+x+=+-16%2F-8+\"
\n" ); document.write( "\"+x+=+2+\"
\n" ); document.write( "Well, yes, 2 is 1/2 way between 1 and 3 so this makes sense.
\n" ); document.write( "Plug this x value into the original equation.\r
\n" ); document.write( "\n" ); document.write( "\"+y+=+-4x%5E2+%2B16x+-+12+\"
\n" ); document.write( "\"+y+=+-4%282%29%5E2+%2B16%282%29+-+12+\"
\n" ); document.write( "\"+y+=+-4%284%29+%2B16%282%29+-+12+\"
\n" ); document.write( "\"+y+=+-16+%2B16%282%29+-+12+\"
\n" ); document.write( "\"+y+=+-16+%2B32+-+12+\"
\n" ); document.write( "\"+y+=+16+-+12+\"
\n" ); document.write( "\"+y+=+4+\"
\n" ); document.write( "so now your Vertex is (2,4)
\n" ); document.write( "your three point to graph are:
\n" ); document.write( "(1,0) (3,0) (2,4)
\n" ); document.write( "the vertex is a maximum and the Parabala opens down because the leading coefficient is negative.\r
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