document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330078>Question 330078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236527 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court<BR>\n" );
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document.write( "Let L = length<BR>\n" );
document.write( "and W = width<BR>\n" );
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document.write( "Then,<BR>\n" );
document.write( "2(L+W) = 280 (equation 1)<BR>\n" );
document.write( "L = W + 44  (equation 2)<BR>\n" );
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document.write( "Substitute the value of L from equation 2 into equation 1 to solve for W:<BR>\n" );
document.write( "2(L+W) = 280<BR>\n" );
document.write( "2(W+44+W) = 280<BR>\n" );
document.write( "2(2W+44) = 280<BR>\n" );
document.write( "2W+44 = 140<BR>\n" );
document.write( "2W = 96<BR>\n" );
document.write( "W = 48 feet (width)<BR>\n" );
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document.write( "Length:<BR>\n" );
document.write( "W + 44 = 48 + 44 = 92 feet<BR>\n" );
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document.write( "Dimension: 48 by 92 feet </SPAN>\n" );
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