document.write( "Question 330037: Wrongly called for a foul, an angry basketball player throws the ball straight down to the floor. If the ball bounces straight up and returns to the floor 2.5 s after first striking it, what was the ball's greatest height above the floor? \n" ); document.write( "
Algebra.Com's Answer #236493 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! REALLY angry...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "time up = time down , so the ball falls from the peak in 1.25 sec\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "gravitational acceleration (g) is 32 ft/sec^2 ___ that means the velocity increases 32 ft/sec for each second of fall\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "falling for 1.25 sec means the ball is going 40 ft/sec at the bottom (almost 30 mph)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the velocity was zero at the peak , the average velocity is (0 + 40)/2 or 20 ft/sec\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20 ft/sec for 1.25 sec is 25ft ___ two and a half times the height of the rim \n" ); document.write( " |