document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=330002>Question 330002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a traingle is 1/3 as long as its height. If the area is 24 square meters, how long is its base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236492 by </B><A HREF=/tutors/aboutme.mpl?userid=mathslover><B>mathslover(157)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathslover><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathslover><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the height be x<BR>\n" );
document.write( "So the base is x/3 (One third of the height )\r<BR>\n" );
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document.write( "Area of a triangle <BR>\n" );
document.write( "=1/2 * base * height <BR>\n" );
document.write( "According to the given condition \r<BR>\n" );
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document.write( "1/2 * x/3 * x = 24<BR>\n" );
document.write( "x^2/6 = 24<BR>\n" );
document.write( "Multiplying both sides by 6<BR>\n" );
document.write( "x^2 = 24*6<BR>\n" );
document.write( "x^2=144<BR>\n" );
document.write( "x=sqrt(144)<BR>\n" );
document.write( "therefore x=12<BR>\n" );
document.write( "and x/3 = 4<BR>\n" );
document.write( "Base is 4 and height is 12 </SPAN>\n" );
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