document.write( "Question 329953: The perimeter of a rectangle is 56inches. The length exceeds the width by 24 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #236452 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+24 \n" ); document.write( "P=2L+2W \n" ); document.write( "56=2(W+24)+2W \n" ); document.write( "56=2W+48+2W \n" ); document.write( "56=4W+48 \n" ); document.write( "4W=56-48 \n" ); document.write( "4W=8 \n" ); document.write( "W=8/4 \n" ); document.write( "W=2 ANS. FOR THE WIDTH. \n" ); document.write( "L=2+24=26 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "56=2*26+2*2 \n" ); document.write( "56=52+4 \n" ); document.write( "56=56 \n" ); document.write( " |