document.write( "Question 329953: The perimeter of a rectangle is 56inches. The length exceeds the width by 24 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #236452 by checkley77(12844)\"\" \"About 
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L=W+24
\n" ); document.write( "P=2L+2W
\n" ); document.write( "56=2(W+24)+2W
\n" ); document.write( "56=2W+48+2W
\n" ); document.write( "56=4W+48
\n" ); document.write( "4W=56-48
\n" ); document.write( "4W=8
\n" ); document.write( "W=8/4
\n" ); document.write( "W=2 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2+24=26 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "56=2*26+2*2
\n" ); document.write( "56=52+4
\n" ); document.write( "56=56
\n" ); document.write( "
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