document.write( "Question 329966: If the perimeter of a rectangle is 68 inches and the length is 12 inches longer than the width, what is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #236446 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
L=W+12
\n" ); document.write( "P=2L+2W
\n" ); document.write( "68=2(W+12)+2W
\n" ); document.write( "68=2W+24+2W
\n" ); document.write( "68=4W+24
\n" ); document.write( "4W=68-24
\n" ); document.write( "4W=44
\n" ); document.write( "W=44/4
\n" ); document.write( "W=11 ANS. FOR THE WIDTH.
\n" ); document.write( "L=11+12=23 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "68=2*23+2*11
\n" ); document.write( "68=46+22
\n" ); document.write( "68=68
\n" ); document.write( "
\n" );