document.write( "Question 329852: David is twice as old as his daughter. In 4 years, David's age will be three times what his daughter's age was 6 years ago. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #236424 by galactus(183)![]() ![]() You can put this solution on YOUR website! Let D=David's age now and d=daughters age now.\r \n" ); document.write( "\n" ); document.write( "David is twice her age: D=2d\r \n" ); document.write( "\n" ); document.write( "4 years from now, David's age: D+4\r \n" ); document.write( "\n" ); document.write( "is 3 times his daughters age 6 years ago: 3(d-6)\r \n" ); document.write( "\n" ); document.write( "So, put it together and we have D+4=3(d-6)\r \n" ); document.write( "\n" ); document.write( "Make the sub D=2d and we have 2d+4=3(d-6)\r \n" ); document.write( "\n" ); document.write( "d=22 and D=44\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |