document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329828>Question 329828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solution A is 10% sugar while Solution B is 30% sugar.A chemist wants to have a 60-liter mixture of solutions A and B with 18% sugar.How many liters of each solution should he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236417 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution A is 10% sugar while Solution B is 30% sugar.A chemist wants to have a 60-liter mixture of solutions A and B with 18% sugar.How many liters of each solution should he use?<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "sugar + sugar = sugar<BR>\n" );
document.write( "0.10x + 0.30(60-x) = 0.18*60<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "10x + 30*60 - 30x = 18*60<BR>\n" );
document.write( "-20x = -12*60<BR>\n" );
document.write( "x = 36 liters (amt. of 10% solution needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "60-x = 24 liters (amt of 0.30% solution needed in the mixture)<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );