document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329750>Question 329750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me in this question\r<BR>\n" );
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document.write( "give the equation of the line whose graph is parallel to 2x + 3y = -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236405 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + 3y = -1<BR>\n" );
document.write( "3y=-2x-1<BR>\n" );
document.write( "y= -2/3 *x -1/3<BR>\n" );
document.write( "slope m  = -2/3\r<BR>\n" );
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document.write( "the equation of a line  parallel to the above line will be<BR>\n" );
document.write( "y=-2x/3 +c </SPAN>\n" );
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