document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329804>Question 329804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with factoring <BR>\n" );
document.write( "3+5x-2x^2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236390 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3+5x-2x^2=0<BR>\n" );
document.write( "-2x^2+5x+3=0<BR>\n" );
document.write( "2x^2-5x-3=0 multiply each side by -1<BR>\n" );
document.write( "2*-3=-6. The 2 factors of -6 whose sum is -5 are -6 and 1.<BR>\n" );
document.write( "2x^2+x-6x-3=0<BR>\n" );
document.write( "x(2x+1)-3(2x+1)=0<BR>\n" );
document.write( "(x-3)(2x+1)=0 factoring by grouping<BR>\n" );
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document.write( "x=3<BR>\n" );
document.write( "2x=-1, x=-1/2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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