document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329700>Question 329700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know answer but not how to get it, please show detailed step by step, thank you.\r<BR>\n" );
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document.write( "(x+5)^1/3 - (x+5)^4/3\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "it's 6 over first term in parentheses,minus, the 1 is over x-8, but computer won't keep it there.  divided by term below line.  thank you.\r<BR>\n" );
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document.write( "    6                      1<BR>\n" );
document.write( "---------         -     -----<BR>\n" );
document.write( "(x^2 -3x -40)         (x-8)<BR>\n" );
document.write( "________________________\r<BR>\n" );
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document.write( "       1<BR>\n" );
document.write( "      ---  +1<BR>\n" );
document.write( "      x+5  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236389 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+5)^1/3 - (x+5)^4/3<BR>\n" );
document.write( "(x+5)^1/3( 1-(x+5)^3)<BR>\n" );
document.write( "(x+5)^1/3(1-x-5)(1+5x+25)<BR>\n" );
document.write( "(x+5)^1/3(-x-4)(5x+26)<BR>\n" );
document.write( "(x+5)^1/3 (-5x^2-26x-20x-104)<BR>\n" );
document.write( "(x+5)^1/3(-5x^2-46x-104)<BR>\n" );
document.write( "-(x+5)^1/3(5x^2-20x-26x-104)<BR>\n" );
document.write( "-(x+5)^1/3{5x(x-4)-26(x-4)}<BR>\n" );
document.write( "-(x+5)^1/3(x-4)(5x-26)\r<BR>\n" );
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document.write( " ....\r<BR>\n" );
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document.write( "it's 6 over first term in parentheses,minus, the 1 is over x-8, but computer won't keep it there.  divided by term below line.  thank you.\r<BR>\n" );
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document.write( "    6                      1<BR>\n" );
document.write( "---------         -     -----<BR>\n" );
document.write( "(x^2 -3x -40)         (x-8)<BR>\n" );
document.write( "________________________\r<BR>\n" );
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document.write( "       1<BR>\n" );
document.write( "      ---  +1<BR>\n" );
document.write( "      x+5 \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%286%2F%28x-8%29%28x%2B5%29%29++-+%281%2F%28x-8%29%29%29++%2F++%28+%28x%2B6%29%2F%28x%2B5%29%29%0D%0A...%0D%0AlCD++%28x-8%29%28x%2B5%29%0D%0A...%0D%0A%7B%7B%7B%28%286-%28x%2B5%29%29%2F%28x-8%29%28x%2B5%29%29++%2A+%28%28x%2B5%29%2F%28x%2B6%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-x%2B1%29%2F%28x-8%29%28x%2B5%29+%2A+%28x%2B5%29%2F%28x%2B6%29 ALIGN=MIDDLE  ALT=\"%28-x%2B1%29%2F%28x-8%29%28x%2B5%29+%2A+%28x%2B5%29%2F%28x%2B6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "..<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-%28x-1%29%29%2F%28%28x-8%29%28x%2B6%29%29 ALIGN=MIDDLE  ALT=\"%28-%28x-1%29%29%2F%28%28x-8%29%28x%2B6%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );