document.write( "Question 329761: Given a mean of 120 and a standard deviation of 5.5, find the 95th percentile. \n" ); document.write( "
Algebra.Com's Answer #236360 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Given a mean of 120 and a standard deviation of 5.5, \n" ); document.write( "find the 95th percentile. \n" ); document.write( "---- \n" ); document.write( "Find the z-value with a left tail of 0.95. \n" ); document.write( "--- \n" ); document.write( "invNorm(0.95) = 1.645 \n" ); document.write( "--- \n" ); document.write( "Use x = zs+u to find the 95th% score. \n" ); document.write( "--- \n" ); document.write( "x = 1.645*5.5+120 = 129.05 \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |