document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329661>Question 329661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One day last summer, Jim went kayaking on the Little Susitna River in Alaska. Paddling upstream against the current, he traveled 20 miles in 4 hours. Then he turned around and paddled twice as fast downstream and, with the help of the current, traveled 19 miles in 1 hour. Find the rate of the current.\r<BR>\n" );
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document.write( "Thanks!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236348 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Paddling upstream against the current, he traveled 20 miles in 4 hours.<BR>\n" );
document.write( " Then he turned around and paddled twice as fast downstream and, with the help of the<BR>\n" );
document.write( " current, traveled 19 miles in 1 hour.<BR>\n" );
document.write( " Find the rate of the current. <BR>\n" );
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document.write( "Let s = normal speed in still water<BR>\n" );
document.write( "Let c = rate of the current<BR>\n" );
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document.write( "Find his actual speed going up stream<BR>\n" );
document.write( "20/4 = 5 mph upstream<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(s - c) = 5<BR>\n" );
document.write( "s = (c+5)<BR>\n" );
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document.write( "2s = fast speed down stream<BR>\n" );
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document.write( "Write a distance equation for downstream; dist = time * speed<BR>\n" );
document.write( "1(2s + c) = 19<BR>\n" );
document.write( "2s + c = 19<BR>\n" );
document.write( "Replace s with (c+5)<BR>\n" );
document.write( "2(c+5) + c = 19<BR>\n" );
document.write( "2c + 10 + c = 19<BR>\n" );
document.write( "2c + c = 19 = 10<BR>\n" );
document.write( "3c = 9<BR>\n" );
document.write( "c = 3 mph is the current <BR>\n" );
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document.write( "Check solution by finding the speed in still water<BR>\n" );
document.write( "s = 3 + 5 = 8 mph<BR>\n" );
document.write( "\"paddled twice as fast downstream and, with the help of the<BR>\n" );
document.write( " current, traveled 19 miles in 1 hour.\"<BR>\n" );
document.write( "2(8) + 3 = 19<BR>\n" );
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