document.write( "Question 329705: solve for t: at^2 + cz = b \n" ); document.write( "
Algebra.Com's Answer #236347 by checkley77(12844)\"\" \"About 
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at^2 + cz = b subtract cz.
\n" ); document.write( "at^2=b-cz divide by a.
\n" ); document.write( "t^2=(b-cz)/a take the sqrt.
\n" ); document.write( "t=sqrt(b-cz)/a ans.
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