document.write( "Question 329724: A rectangular building contains 3600 square ft. How many feet are in the perimeter of the lot? \n" ); document.write( "
Algebra.Com's Answer #236329 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
This problem has an infinite number of solutions.
\n" ); document.write( "Im assuming the building is the same as the lot size.
\n" ); document.write( "3,600=xy
\n" ); document.write( "Let x=60 & y=60
\n" ); document.write( "60*60=3,600
\n" ); document.write( "Then the perimeter would be:
\n" ); document.write( "2*60+2*60=120+120=240 ft.
\n" ); document.write( "------------------------------
\n" ); document.write( "But let x=120 & y=30
\n" ); document.write( "120*30=3,600
\n" ); document.write( "Now the perimeter is:
\n" ); document.write( "2*120+2*30=240+50=290 ft.
\n" ); document.write( "-------------------------------
\n" ); document.write( "But let x=100 & y=36
\n" ); document.write( "100*36=3,6000
\n" ); document.write( "Now the perimeter is:
\n" ); document.write( "2*100+2*36=200+72=272 ft.
\n" ); document.write( " \n" ); document.write( "
\n" );