document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329620>Question 329620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of \"a\" if a line containing the point (a,-2a) has a y-intercept of 6 and slope of -2/3.\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236283 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of \"a\" if a line containing the point (a,-2a) has a y-intercept of 6 and slope of -2/3.<BR>\n" );
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document.write( "Using slope and intercept info you get:<BR>\n" );
document.write( "y = (-2/3)x+6<BR>\n" );
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document.write( "Using the point info you get:<BR>\n" );
document.write( "-2a = (-2/3)a+6<BR>\n" );
document.write( "Multiply thru by 3 to get:<BR>\n" );
document.write( "-6a = -2a + 18<BR>\n" );
document.write( "Solve for \"a\":<BR>\n" );
document.write( "4a = -18<BR>\n" );
document.write( "a = -9/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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