document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329568>Question 329568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular field has a perimeter of 220 meters and an area of 2,856 square meters. What are its dimensions?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236253 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L+W=110<BR>\n" );
document.write( "L*W= 2856<BR>\n" );
document.write( "..<BR>\n" );
document.write( "w=110-L<BR>\n" );
document.write( "L*(110-L)=2856<BR>\n" );
document.write( "110L-L^2=2856<BR>\n" );
document.write( "L^2-110L+2856=0<BR>\n" );
document.write( "L^2_68L-42L+2856=0<BR>\n" );
document.write( "L(L-68)-42(L-68)=0<BR>\n" );
document.write( "(L-68)(L-42)=0<BR>\n" );
document.write( "L=62 OR 48\r<BR>\n" );
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document.write( "The dimensions are 62 by 48 meters </SPAN>\n" );
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