document.write( "Question 329536: Solve 5^2x+1 >(or equal to) 50 \n" ); document.write( "

Algebra.Com's Answer #236245 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5%5E%282x%2B1%29%3E=50\"$
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\n" ); document.write( " $\"2x%2B1%3E=log%28%2850%29%29%2Flog%28%285%29%29\"$
\n" ); document.write( " $\"2x%3E=log%28%2850%29%29%2Flog%28%285%29%29-1\"$
\n" ); document.write( " $\"+x%3E=%281%2F2%29%28log%28%2850%29%29%2Flog%28%285%29%29-1%29+\"$
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