document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=329560>Question 329560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I find x? My problem is (1/4)^(x-1)=32^(x+3). I've tried plugging in numbers but my teacher showed us a formula I think but I never understood it.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #236228 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=236228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How would I find x? My problem is (1/4)^(x-1)=32^(x+3). I've tried plugging in numbers but my teacher showed us a formula I think but I never understood it.<BR>\n" );
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document.write( "(1/4)^(x-1)=32^(x+3)<BR>\n" );
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document.write( "Change both sides to a common base as follows:<BR>\n" );
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document.write( "[(2^-2)^(x-1)] = [(2^5)^(x+3)]<BR>\n" );
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document.write( "2^(-2x+2) = 2^(5x+15)<BR>\n" );
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document.write( "Equate the exponents:<BR>\n" );
document.write( "-2x+2 = 5x+15<BR>\n" );
document.write( "7x = -13<BR>\n" );
document.write( "x = -13/7<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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