document.write( "Question 329502: Trains A and B are traveling the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 70 miles per hour. Train A passes a station at 1:10 P.M. If train B passes the station at 1:22 P.M. at what time will train B catch up with train A?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #236210 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Trains A and B are traveling the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 60 miles per hour and train B is traveling at 70 miles per hour.
\n" ); document.write( " Train A passes a station at 1:10 P.M.
\n" ); document.write( "If train B passes the station at 1:22 P.M. at what time will train B catch up with train A?
\n" ); document.write( ":
\n" ); document.write( "from the given information, we know that train B is 12 min (1/5 hr) behind
\n" ); document.write( " train A, when train A passes the station
\n" ); document.write( ":
\n" ); document.write( "The distance between the trains at this time: \"1%2F5\" * 70 = 14 mi
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for train B to catch train A
\n" ); document.write( ":
\n" ); document.write( "write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Train B travel dist = Train A travel dist + 14 mi
\n" ); document.write( "70t = 60t + 14
\n" ); document.write( "70t - 60t = 14
\n" ); document.write( "10t = 14
\n" ); document.write( "t = \"14%2F10\"
\n" ); document.write( "t = 1.4 hr or 1 hr 24 min
\n" ); document.write( ":
\n" ); document.write( "1:10 + 1:24 = 2:34 pm, B catches A
\n" ); document.write( "
\n" );