document.write( "Question 329512: I'm kinda stuck on these three identity Questions: Could you explain how to solve these to me. Please and Thankyou.
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document.write( "6. Find the exact value of sin 2 θ given that cos θ = 12/13 and θ is in Quadrant I.
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document.write( "a. -120/169
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document.write( "b. 120/169
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document.write( "c. 60/169
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document.write( "d. -60/169
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document.write( "*sin(2θ)=2sin(θ)cos(θ)
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document.write( "sin(2θ)=2sin(θ)cos(12/13)
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document.write( "sin(2θ)=?\r
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document.write( "8. Find the value of the tan of a/2 given that cos a = -4/5 and a is in Quadrant II.
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document.write( "a. 3
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document.write( "b. 1/2
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document.write( "c. -2
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document.write( "d. -1/2
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document.write( "*tan(a/2)=1-cos(a)/sin(a)
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document.write( "tan(a/2)=1-cos(-4/5)/sin(1/5)
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document.write( "tan(a/2)=?\r
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document.write( "14. Evaluate sin 165 ° + sin 105 ° .
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document.write( "*My answer was -√(2)/2. Am I correct?
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document.write( "15. Evaluate sin(π/12)-sin((5π)/12).
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document.write( "*My answer was 1. Am I correct? \n" );
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Algebra.Com's Answer #236194 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! BIG TIP: Post one question at a time or else no one will reply.\r \n" ); document.write( "\n" ); document.write( "I will do question 6 only.\r \n" ); document.write( "\n" ); document.write( "6. Find the exact value of sin 2 θ given that cos θ = 12/13 and θ is in Quadrant I.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are in quadrant 1 which means all trig functions are positive. So, there's no need to worry about signs in this case.\r \n" ); document.write( "\n" ); document.write( "Using a right triangle in the first quadrant, we know that cos(theta) = adj/hyp. \n" ); document.write( "Using the Pythagorean Theorem, we also learn that the missing side is 5. \r \n" ); document.write( "\n" ); document.write( "sin(theta) = opp/hyp\r \n" ); document.write( "\n" ); document.write( "sin(theta) = 5/13\r \n" ); document.write( "\n" ); document.write( "cos(theta) = adj/hyp\r \n" ); document.write( "\n" ); document.write( "cos(theta) = 12/13\r \n" ); document.write( "\n" ); document.write( "We now plug it into the formula sin(2θ) = 2sin(θ)cos(θ) and simplify.\r \n" ); document.write( "\n" ); document.write( "sin(2θ) = 2(5/13)(12/13)\r \n" ); document.write( "\n" ); document.write( "sin(2θ) = 2(5/13)(12/13)\r \n" ); document.write( "\n" ); document.write( "sin(2θ) = 120/169\r \n" ); document.write( "\n" ); document.write( "CHOICE B\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |