document.write( "Question 329444: If y varies inversely as the square of x and y = 1 when x = 2, what is the value of y when x = -4? \n" ); document.write( "
Algebra.Com's Answer #236151 by nyc_function(2741)\"\" \"About 
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y = k/x^2\r
\n" ); document.write( "\n" ); document.write( "We need to find k first.\r
\n" ); document.write( "\n" ); document.write( "Let y = 1, when x = 2 to find k.\r
\n" ); document.write( "\n" ); document.write( "1 = k/(2)^2\r
\n" ); document.write( "\n" ); document.write( "1 = k/4\r
\n" ); document.write( "\n" ); document.write( "1*4 = k\r
\n" ); document.write( "\n" ); document.write( "4 = k\r
\n" ); document.write( "\n" ); document.write( "We now need to find y when k = 4 and x = -4.\r
\n" ); document.write( "\n" ); document.write( "y = k/x^2\r
\n" ); document.write( "\n" ); document.write( "y = 4/(-4)^2\r
\n" ); document.write( "\n" ); document.write( "y = 4/16\r
\n" ); document.write( "\n" ); document.write( "y = 1/4\r
\n" ); document.write( "\n" ); document.write( "Done!
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